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2x^2+1x+8x-4=0
We add all the numbers together, and all the variables
2x^2+9x-4=0
a = 2; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·2·(-4)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{113}}{2*2}=\frac{-9-\sqrt{113}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{113}}{2*2}=\frac{-9+\sqrt{113}}{4} $
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